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Offline gambol1
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« Reply #40 on: September 20, 2011, 01:22:19 pm »
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Granted you have to supply enough amperage capacity but the internal design of the circuit and the voltage determine the amperage. Does this help?

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Offline overhill
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« Reply #41 on: September 20, 2011, 04:14:07 pm »
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Quote:Posted by gambol1
Granted you have to supply enough amperage capacity but the internal design of the circuit and the voltage determine the amperage. Does this help?

Yes, however if the designed circuit doesnot draw the required amperage, there is unwanted resistance or an open. If it draws excessive current there is a short or worn component in the system. A normally operating system will not use any more current than for what it was designed. That current may vary by mode of operation such as start-up, pin-point etc. Bear in mind that an inconsistent voltage (weak batteries or poor connections) will affect current flow.


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Offline GoldDigger1950
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« Reply #42 on: September 20, 2011, 04:24:52 pm »
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Quote:Posted by overhill
Yes, however if the designed circuit doesnot draw the required amperage, there is unwanted resistance or an open. If it draws excessive current there is a short or worn component in the system. A normally operating system will not use any more current than for what it was designed. That current may vary by mode of operation such as start-up, pin-point etc. Bear in mind that an inconsistent voltage (weak batteries or poor connections) will affect current flow.


Where did you ever get such a notion? The load circuit will draw what it draws. A 500ma circuit will draw 500ma even if the power supply is rated at 100 times that amount. There is no loss to resistance or any open circuit condition. The current available will be 5 amps in such a hypothetical circumstance but the draw from the supply will be 500ma and no more. Unless there is a circuit fault and then it will draw whatever the fault requires.

Look, this isn't a debate. This is fact. The only exception to his is a unique type of power supply known as the Constant Current Source which is used mostly in instrumentation and measurement equipment. If you hooked up a load circuit to one of those, you're most likely fry it.

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« Reply #43 on: September 20, 2011, 05:15:58 pm »
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Quote:Posted by GoldDigger1950
Where did you ever get such a notion? The load circuit will draw what it draws. A 500ma circuit will draw 500ma even if the power supply is rated at 100 times that amount. There is no loss to resistance or any open circuit condition. The current available will be 5 amps in such a hypothetical circumstance but the draw from the supply will be 500ma and no more. Unless there is a circuit fault and then it will draw whatever the fault requires.

You are agreeing with me. the circuit will draw no more than its design under normal conditions. that's what i said. i never said there was a loss to resistance in an open circuit. I said that if you do not measure the required amperage, than you have an open (no amps) or resistance (low amps). And as you say if there is a short, the amps will go out of sight. And we agree that it will use only the amount of current for which it was designed. I was only trying to explain the results of using the ammeter to test the system. Perhaps i should have been clearer. No debate. just me not being clear. I think if you reread it, you will see where i was trying to go. Thanks Conner

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« Last Edit: September 20, 2011, 05:23:26 pm by GoldDigger1950 »
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Offline GoldDigger1950
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« Reply #44 on: September 20, 2011, 05:24:57 pm »
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Fair enough, mate. I apologize for the misunderstanding. Often we get comments on technical threads from those who don't have a clue that wind up misleading people. On another electronics forum, a guy tried powering a scooter motor with a wall cube designed to charge the battery. Worked for about 3 seconds and then smoke and fire ensued. It seems the charger wasn't a simple wall cube after all. It was a constant current charger designed for sealed lead-acid batteries.

A painful and costly lesson for him.

Posted on: September 21, 2011, 01:22:09 AM
Quote:Posted by overhill
the circuit will draw no more than its design under normal conditions.

I corrected a typo in this sentence that was essential to your meaning. I changed the word "to" to "no" just before the word more.

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« Reply #45 on: September 20, 2011, 05:35:31 pm »
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Quote:Posted by GoldDigger1950
A painful and costly lesson for him.

Before i retired, i was a trainer for Delphi corp. teaching car dealer technicians how to repair vehicle electronics and engine management systems. The horror stories i heard and the damage i had seen were unbelievable.
Thank you sir.


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Offline GoldDigger1950
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« Reply #46 on: September 20, 2011, 07:50:13 pm »
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Quote:Posted by overhill
Before i retired, i was a trainer for Delphi corp. teaching car dealer technicians how to repair vehicle electronics and engine management systems. The horror stories i heard and the damage i had seen were unbelievable.

A fellow hooked his battery up backwards one day. His horn sucked, his radio listened and his lights cast a shadow.

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« Reply #47 on: September 20, 2011, 07:53:25 pm »
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LOL! Reminds me of the Time I saw God after touching a Jacobs Latter in action!

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« Last Edit: September 21, 2011, 07:35:33 am by homefire »
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« Reply #48 on: September 20, 2011, 10:39:27 pm »
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You two guys crack me up. Grin Grin Grin

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« Reply #49 on: September 21, 2011, 03:36:14 pm »
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Quote:Posted by GoldDigger1950
A fellow hooked his battery up backwards one day. His horn sucked, his radio listened and his lights cast a shadow.



I'll have to remember that one!!! Grin Grin Grin   That cracked me up!

Posted on: September 21, 2011, 03:33:10 PM
Quote:Posted by homefire
LOL! Reminds me of the Time I saw God after touching a Jacobs Latter in action!



Good one Homefire! One question.... Did you sleep with your head on the rock?  Grin  Or maybe the floor! Cheesy Cheesy Cheesy

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